Posted by lionkor 1 day ago
This year, I’ve finally taken the plunge to properly learn Rust (I’ve used it for little things over the years, but never for anything particularly extensive) and one thing that jumped out at me is that you don’t need to think about it, because Rust makes it explicit: everything is statically known unless you explicitly ask for it to be virtual.
It’s was a little annoying at first because some things don’t just work automatically, but once I got used to it, it was wonderful to never have to think about when the compiler might do something. You also don’t need dynamism most of the time.
I still like tinkering in C++, but I probably wouldn’t choose it for a serious project anymore.
This is true in C++ also...
In such cases I prefer using std::variant instead of inheritance, but this works only if all possible types are known ahead of time.
It seems that for devirtualization GCC has a warning option -Wsuggest-final-types which is supposed to tell when devirtualization fails in link-time optimization. Not sure how reliable that is, or whether it will produce gobs of unhelpful warnings. Maybe it could be combined with some kind of hint that we want this particular call to be devirtualized, and don't care about calls without the hint.
Clang relied on checking the address of a function pointer in the vtable to validate the class was the type it expected, but it wasn’t necessarily the function that is currently being called. But due to ICF two different subclasses with two different functions shared the same address, so the code made incorrect assumptions about the type. Then it promptly segfaulted.
A pedantic Pete would mention C++ has member functions.
Go Pete!
Re "When we know the dynamic type", I made a similar assertion on HN years ago, and of course it turned out that there's a weird wrinkle:
If the code in your snippet is expanded to:
Derived d;
Base *p = &d;
any_external_func(); // Added
p->f();
where any_external_func() is defined in some other translation unit (and, I'm now fairly sure, Derived's ctor is also defined in another translation unit, or it transitively calls something that is), this would seem not to affect anything -- but in fact the compiler must not assume that p's dynamic type is still Derived by the final line. Why? Because the following insane sequence of events might have happened:1. d's ctor registers its this pointer in some global table.
2. Using this table, any_external_func() calls d's dtor and then overwrites it in place with a fresh instance of Base using placement new, which replaces everything, including its vtable, meaning that p->f() should call Base's version, not Derived's.
(It might be UB to call placement new on static or automatic storage holding an in-lifetime object, I don't know. If so, the above construction is moot -- but the closely analogous situation where we instead dynamically allocate dp = new Derived() still goes through, and is nearly as surprising.)